Algebra - Mathematics Multiple Choice questions

Consider the following two sets of equations :
I. 2x - y = 0 and 6x - 3y = 0
II. 3x - 4y = 0 and 12x - 20y = 0

A. both sets I and II possess unique solutions.

B. Set I possesses unique solution and set II has infinitely many solutions.

C. Set II possesses unique solution and set I possesses infinitely many solutions.

D. None of the sets I and II possesses a unique solution.

E. None of the above

View Answer View Explanation

C. SET II POSSESSES UNIQUE SOLUTION AND SET I POSSESSES INFINITELY MANY SOLUTIONS.

Posted in: Linear Equations - Algebra - Mathematics

If 2x + 3y = 5 and x = - 2, then the value of y is:

A. 1/3

B. 1

C. 3

D. 9

E. None of the above

View Answer View Explanation

C. 3

Posted in: Linear Equations - Algebra - Mathematics

Find the values of k ε R subject to the following condition :
Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

A. 12

B. - 1

C. 2

D. 0, 12

E. None of the above

View Answer View Explanation

D. 0, 12

Posted in: Quadratic Equations - Algebra - Mathematics

If (x + ¹/_x) = 4, then (x⁴ + ¹/x⁴)_{is equal to :}

A. 196

B. 194

C. 192

D. 190

E. None of the above

View Answer View Explanation

B. 194

Posted in: Basic Operations & Factorization - Algebra - Mathematics

If x³ + 6x²+ 4x + k is exactly divisible by (x + 2), then the value of k is :

A. - 6

B. - 7

C. - 8

D. - 10

E. None of the above

View Answer View Explanation

C. - 8

Posted in: Basic Operations & Factorization - Algebra - Mathematics

Consider the following two sets of equations :I. 2x - y = 0 and 6x - 3y = 0II. 3x - 4y = 0 and 12x - 20y = 0

If 2x + 3y = 5 and x = - 2, then the value of y is:

Find the values of k ε R subject to the following condition :Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

If (x + 1/x) = 4, then (x4 + 1/x4) is equal to :

If x3 + 6x2 + 4x + k is exactly divisible by (x + 2), then the value of k is :

Consider the following two sets of equations :
I. 2x - y = 0 and 6x - 3y = 0
II. 3x - 4y = 0 and 12x - 20y = 0

Find the values of k ε R subject to the following condition :
Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

If (x + ¹/_x) = 4, then (x⁴ + ¹/x⁴)_{is equal to :}

If x³ + 6x²+ 4x + k is exactly divisible by (x + 2), then the value of k is :