Mathematics Multiple Choice questions

Mohan and Sohan working separately can dig a trench in 10 days and 12 days respectively. If they work for 1 day alternately, Mohan begins it, in how many days Mohan will dug the trench ?

A. 22 days

B. $16{1/2}$ days

C. $11{2/3}$ days

D. $10{5/6}$ days

E. None of the above

View Answer View Explanation

D. $10{5/6}$ DAYS

Posted in: Time & Work - Aptitude - Mathematics

If (x + ¹/_x) = 4, then (x⁴ + ¹/x⁴)_{is equal to :}

A. 196

B. 194

C. 192

D. 190

E. None of the above

View Answer View Explanation

B. 194

Posted in: Basic Operations & Factorization - Algebra - Mathematics

Find the values of k ε R subject to the following condition :
Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

A. 12

B. - 1

C. 2

D. 0, 12

E. None of the above

View Answer View Explanation

D. 0, 12

Posted in: Quadratic Equations - Algebra - Mathematics

If x³ + 6x²+ 4x + k is exactly divisible by (x + 2), then the value of k is :

A. - 6

B. - 7

C. - 8

D. - 10

E. None of the above

View Answer View Explanation

C. - 8

Posted in: Basic Operations & Factorization - Algebra - Mathematics

(x²⁹ - x²⁵ + x¹³ - 1) is divisible by:

A. both (x - 1) & (x + 1)

B. (x - 1) but not by (x + 1)

C. (x + 1) but not by (x - 1)

D. neither (x - 1) nor (x + 1)

E. None of the above

View Answer View Explanation

B. (X - 1) BUT NOT BY (X + 1)

Posted in: Basic Operations & Factorization - Algebra - Mathematics

Mohan and Sohan working separately can dig a trench in 10 days and 12 days respectively. If they work for 1 day alternately, Mohan begins it, in how many days Mohan will dug the trench ?

If (x + 1/x) = 4, then (x4 + 1/x4) is equal to :

Find the values of k ε R subject to the following condition :Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

If x3 + 6x2 + 4x + k is exactly divisible by (x + 2), then the value of k is :

(x29 - x25 + x13 - 1) is divisible by:

If (x + ¹/_x) = 4, then (x⁴ + ¹/x⁴)_{is equal to :}

Find the values of k ε R subject to the following condition :
Two roots of $x^2 +(k - 2)x + (2k + 1) = 0$ are equal.

If x³ + 6x²+ 4x + k is exactly divisible by (x + 2), then the value of k is :

(x²⁹ - x²⁵ + x¹³ - 1) is divisible by: