If a man reduces his speed to 2/3, he takes 1 hour more in walking a certain distance.
The time (in hours) to cover the distance with his normal speed is :

Answer: A. 2

Suppose man covers x km in y hours.
His normal speed = x/y km/hr
Reduced speed = 2x/3y km/hr.

Time taken to cover x km = x/2x / 3y hrs
= 3y/2 hrs.

By hypothesis,
= 3/2y = y + 1
or
y = 2hrs