If x + y + z = 9  &  xy + yz + zx = 23,
then the value of (x3 + y3 + z3 - 3xyz) is :

Answer: A. 108

-> (x3 + y3 + z3 - 3xyz)
= (x + y + z) (x2 + y2 + z2 - xy - yz - zx)
= (x + y + z) [(x + y + z)- 3(xy + yz + zx)]
= 9 x (81 - 3 x 23)
= (9 x 12)
= 108