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For the quadratic equation 2x^2 - 4x + k = 0 to have real roots, what must be the minimum value of k?

Answer: B. 2
The discriminant must be non-negative for real roots: b^2 - 4ac ? 0. Here, (-4)^2 - 4(2)(k) ? 0 leads to 16 - 8k ? 0, thus k ? 2.
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