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For the quadratic equation 2x² - 4x + k = 0 to have real roots, what must be the minimum value of k?

Answer: B. 2
The discriminant must be non-negative for real roots: D = b² - 4ac = (-4)² - 4(2)(k) ? 0. This simplifies to 16 - 8k ? 0, leading to k ? 2.
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